# largest rectangle in histogram divide and conquer

The largest rectangle is shown in the shaded area, which has area = 10 unit. If the value of this new area is greater, then we will update the maxArea. The rectangles have equal widths but may have different heights. After mho's comments: I mean the area of largest rectangle that fits entirely. http://www.informatik.uni-ulm.de/acm/Locals/2003/html/judge.html. By using our site, you
Once we have the minimum height, what will be the maximum rectangular area if we divide the histogram on the basis of this bar? 6 responses. For each bar, we will move from right to left(from that bar) and will traverse each bar till the starting bar. Now, how will we do this? Previous Next If you want to practice data structure and algorithm programs, you can go through 100+ data structure and algorithm programs. 2) Start from first bar, and do following for every bar ‘hist[i]’ where ‘i’ varies from 0 to n-1. The idea is simple: for a given range of bars, the maximum area can either from left or right half of the bars, or from the area containing the middle two bars. For simplicity, assume that all bars have same width and the width is 1 unit. Given an array with heights (all non-negative) of rectangle (assuming width is 1), we need to find the largest rectangle area possible. By maintaining the minHeight applicable for each bar to be part of a rectangle, we can easily compute the area of the rectangle. The histogram is a graph which consists of bars. ***Largest Rectangle in a Histogram(divide concure +segtree) Problem H: Largest Rectangle in a Histogram Source file: histogram. The idea for this approach is instead of a simple one-by-one traversal of each bar and find the area starting from that bar, we will use the divide and conquer algorithm. We traverse all bars from left to right, maintain a stack of bars. Even though O(n*log(n)) or O(n) is required, there are several kinds of solutions to this problem. Star 0 Fork 1 Star Code Revisions 1 Forks 1. 3) If the stack is not empty, then one by one remove all bars from stack and do step 2.b for every removed bar. C++: 01 class Solution { 02 public: 03 int largestRectangleArea(vector

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